FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen
A:
The character at the end of the path is an escape sequence.
print os.path.normpath(os.path.expanduser(b”\\Users\\User.Name”));
will print
/Users/User.Name/desktop
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FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen
FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen
FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen
When I delete everything after ‘FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen’.
my output is:
[DATA]
A:
Here’s how you can do this with sed. The sed command executes s/FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen/, which removes the line following the match. The replacement is blank.
sed’s/FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen/,/g’ infile
To delete all lines after the match, you can use this sed command:
sed’s/FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen/g’ infile
Since the g at the end is what makes sed delete all the lines, you don’t need to have a blank line between the pattern and the replacement.
EDIT
You could do something like this if you have GNU sed and GNU awk:
sed -n ‘/FSXP3DP3DV4FlyTampaTampaRebootedv24Keygen/q’ infile
This q is the last command in the script, which means delete everything after the match.
Q:
Double free or single free in C
In the following program:
#include
#include
struct node
{
int key;
struct node *next;
};
void print_list(struct node *head)
{
while(head)
{
printf(“%d
“,head->key);
head = head->next;
}
}
int main()
{
struct node *head = NULL;
head = (struct node *)malloc(sizeof(struct node));
head->key = 1;
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